Hitunglah pH hidrolis gram NaCN 0,1 M jika Ka HCN = 4,10 x 10 pangkat -10
Jawaban:
3-log 5
Penjelasan:
Diketahui:
*[HCN] = [H+] = 0,1 M
*Ka HCN = 4.10^-10
Ditanyakan :
*pH
Penyelesaian
[H+] = √Kw x [H+] / Ka
= √10^-14 x 0,1 / 4.10^-10
= √1.10^-15 / 4.10^-10
= √25 x 10^-6
= 5.10^-3
Ph = Log 5.10^-3
PH = 3-log 5